8x^2-38x+39=0

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Solution for 8x^2-38x+39=0 equation: 



8x^2-38x+39=0

a = 8; b = -38; c = +39;
Δ = b2-4ac
Δ = -382-4·8·39
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-14}{2*8}=\frac{24}{16}
=1+1/2
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+14}{2*8}=\frac{52}{16}
=3+1/4
$

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